15w^2+4w-1=2w

Solution for 15w^2+4w-1=2w equation:

15w^2+4w-1=2w

We move all terms to the left:

15w^2+4w-1-(2w)=0

We add all the numbers together, and all the variables

15w^2+2w-1=0

a = 15; b = 2; c = -1;
Δ = b2-4ac
Δ = 22-4·15·(-1)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-8}{2*15}=\frac{-10}{30}
=-1/3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+8}{2*15}=\frac{6}{30}
=1/5
$